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	<title>Comments on: An airplane whose air speed is 620 km/h is supposed to fly in a straight path 35.0 degree?</title>
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		<title>By: Vince</title>
		<link>http://diy-solarpanels.net/air-x-wind/an-airplane-whose-air-speed-is-620-kmh-is-supposed-to-fly-in-a-straight-path-35-0-degree/comment-page-1#comment-1641</link>
		<dc:creator>Vince</dc:creator>
		<pubDate>Sun, 14 Mar 2010 06:13:59 +0000</pubDate>
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		<description>You&#039;ve assumed that the plane will be traveling at a speed of 620 Km/h
in the direction 35NE..  This can&#039;t be right because of the wind.
that speed is one of the unknowns.

however the airspeed in the unknown direction &quot;theta&quot; will be 620 Km/H.

airplane airspeed
y1 =  620 cos(theta) 
x1 =  620 sin(theta)

Note that I used cosine for Y1 
since due north ---&gt; i.e. 0 deg  ===&gt;  Y1 = 620 cos(0) = 620.

wind 
x2 =  0  
y2 = -95. blowing toward the south.

resultant  Vt = v1+v2  must be at 35NE

Xt = 620 sin(theta)
Yt = 620 cos(theta) - 95

tan35 = opposite/adjacent = Xt/Yt 
Note that I used Xt/Yt since  tan(0) is due north when Xt = 0.

Xt = Yt. tan35

Solve for theta. 
620 sin(theta) = (620 cos(theta) - 95) . tan35&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;http://en.wikipedia.org/wiki/Boxing_the_compass</description>
		<content:encoded><![CDATA[<p>You&#8217;ve assumed that the plane will be traveling at a speed of 620 Km/h<br />
in the direction 35NE..  This can&#8217;t be right because of the wind.<br />
that speed is one of the unknowns.</p>
<p>however the airspeed in the unknown direction &quot;theta&quot; will be 620 Km/H.</p>
<p>airplane airspeed<br />
y1 =  620 cos(theta)<br />
x1 =  620 sin(theta)</p>
<p>Note that I used cosine for Y1<br />
since due north &#8212;&gt; i.e. 0 deg  ===&gt;  Y1 = 620 cos(0) = 620.</p>
<p>wind<br />
x2 =  0<br />
y2 = -95. blowing toward the south.</p>
<p>resultant  Vt = v1+v2  must be at 35NE</p>
<p>Xt = 620 sin(theta)<br />
Yt = 620 cos(theta) &#8211; 95</p>
<p>tan35 = opposite/adjacent = Xt/Yt<br />
Note that I used Xt/Yt since  tan(0) is due north when Xt = 0.</p>
<p>Xt = Yt. tan35</p>
<p>Solve for theta.<br />
620 sin(theta) = (620 cos(theta) &#8211; 95) . tan35<br /><b>References : </b><br /><a href="http://en.wikipedia.org/wiki/Boxing_the_compass" rel="nofollow">http://en.wikipedia.org/wiki/Boxing_the_compass</a></p>
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