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	<title>Comments on: The Trajectory Formula with Air resistance. Assistance please?</title>
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		<title>By: Nicholas</title>
		<link>http://diy-solarpanels.net/air-x-wind/the-trajectory-formula-with-air-resistance-assistance-please/comment-page-1#comment-1402</link>
		<dc:creator>Nicholas</dc:creator>
		<pubDate>Fri, 26 Feb 2010 08:59:59 +0000</pubDate>
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		<description>You will not find an accurate trajectory equation for a system with air resistance, because the equations describing the drag force contain constants which can change depending on temperature, orientation of the object, ect.  And it&#039;s difficult to account for these variables, and it can easily result in chaotic behavior.

The equations for the drag force of a fluid are  (air is a fluid)
F = -b v + ½ ρ v² A C 

where
F is the force of drag,
ρ is the density of the fluid,[3]
v is the speed of the object relative to the fluid,
A is the reference area,
C is the drag coefficient (a dimensionless parameter)
and 
b is a constant that depends on the properties of the fluid and the dimensions of the object.

Usually, you can ignore one of these two terms, depending on whether you&#039;re at high or low speeds.  At high speeds v² &gt; v ==&gt; ρ v² A C &gt; b v
At low speeds, v &gt; v² ==&gt; b v &gt; ρ v² A C

For a launching a cannon ball, you&#039;ll probably work in the region of high speeds, and can just use the equation

m y″ = -½ ρ A C ( (x′)²+ (y′)² )   - mg
m x″ = -½ ρ A C ( (x′)²+ (y′)² )

The problem in solving these equations is that C, the drag coefficient, isn&#039;t constant.  If you assume it&#039;s constant, then you can solve these coupled differential equations to get trajectory equations.

You should look at the you wikipedia link below which does give the equation for a falling object, but not an equation of an object with a non-zero component of velocity on the x-direction.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;http://en.wikipedia.org/wiki/Air_resistance</description>
		<content:encoded><![CDATA[<p>You will not find an accurate trajectory equation for a system with air resistance, because the equations describing the drag force contain constants which can change depending on temperature, orientation of the object, ect.  And it&#8217;s difficult to account for these variables, and it can easily result in chaotic behavior.</p>
<p>The equations for the drag force of a fluid are  (air is a fluid)<br />
F = -b v + ½ ρ v² A C </p>
<p>where<br />
F is the force of drag,<br />
ρ is the density of the fluid,[3]<br />
v is the speed of the object relative to the fluid,<br />
A is the reference area,<br />
C is the drag coefficient (a dimensionless parameter)<br />
and<br />
b is a constant that depends on the properties of the fluid and the dimensions of the object.</p>
<p>Usually, you can ignore one of these two terms, depending on whether you&#8217;re at high or low speeds.  At high speeds v² &gt; v ==&gt; ρ v² A C &gt; b v<br />
At low speeds, v &gt; v² ==&gt; b v &gt; ρ v² A C</p>
<p>For a launching a cannon ball, you&#8217;ll probably work in the region of high speeds, and can just use the equation</p>
<p>m y″ = -½ ρ A C ( (x′)²+ (y′)² )   &#8211; mg<br />
m x″ = -½ ρ A C ( (x′)²+ (y′)² )</p>
<p>The problem in solving these equations is that C, the drag coefficient, isn&#8217;t constant.  If you assume it&#8217;s constant, then you can solve these coupled differential equations to get trajectory equations.</p>
<p>You should look at the you wikipedia link below which does give the equation for a falling object, but not an equation of an object with a non-zero component of velocity on the x-direction.<br /><b>References : </b><br /><a href="http://en.wikipedia.org/wiki/Air_resistance" rel="nofollow">http://en.wikipedia.org/wiki/Air_resistance</a></p>
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